ijulijuli23
03.04.2020 12:09

Найдите f'(x0), если
1) f(x) =(x^2+3x-4)^2-sinпx xo=-1
2)f(x)=1/cos x/3 xo=-3п

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Ответ:
аля668
29.05.2021 13:43

Найдем решения неравенства Ix-5I≤2; -2≤х-6≤2; 4≤х≤8- отрезок длиной  4

Найдем решения неравенства Ix-6I≥1

x-6≥1; х≥7  или х-6≤-1;  х≤5; т.е. х∈(-∞;5]∪[7;8]

Из отрезка [4;8] выпадает только отрезок[5;7] длины 2

Используя геометрическое определение вероятности, найдем искомую вероятность, длина решений второго неравенства, которое находится в первом, составляет 2, это сумма длин отрезков  [4;5] и  [7;8], т.е. число благоприятствующих исходов равно 2, а  общее число исходов 4, значит, вероятность равна 2/4=0.5

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Ответ:
07Лизочек07
04.07.2022 06:50

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