Вариант 311. -4х – 11 = -5х – 122. 5(2x – 1) + х - вопрос №10051143311411512252163311573 от FreddikSmall 06.02.2021 22:16

Question

Алгебра: Вариант 311. -4х – 11 = -5х – 122. 5(2x – 1) + х = 63. 3x + 11 = 5х + 7(3х – 5)4. 3х – 4(5х + 2) = 3(7x – 2)5. 17 – 2(3х – 5) — 5(4х – 1) =6x6. –11х + 3(х – 3) = – 8x – 9​

FreddikSmall · Answer

5. ответ: х- любое число...

Вариант 311. -4х – 11 = -5х – 122. 5(2x – 1) + х = 63. 3x + 11 = 5х + 7(3х – 5)4. 3х – 4(5х + 2) = 3(7x – 2)5. 17 – 2(3х – 5) — 5(4х – 1) =6x6. –11х + 3(х – 3) = – 8x – 9​

Вариант 31
1. -4х – 11 = -5х – 12
2. 5(2x – 1) + х = 6
3. 3x + 11 = 5х + 7(3х – 5)
4. 3х – 4(5х + 2) = 3(7x – 2)
5. 17 – 2(3х – 5) — 5(4х – 1) =
6x
6. –11х + 3(х – 3) = – 8x – 9