f(x) = x³ - x² - x + 2
f'(x) = (x³)' - (x²)' - x' + 2' = 3x² - 2x - 1
f'(- 3) = 3 * (- 3)² - 2 * (- 3) - 1 = 3 * 9 + 6 - 1 = 27 + 5 = 32
ответ : f'(- 3) = 32
