2 6x2 – 7x – (3x2 + 47°) + (-2x² + 3x) = (6x2 - вопрос №1491961626273247236273 от PolinaCat29 09.03.2021 18:36

Question

Алгебра: 2 6x2 – 7x – (3x2 + 47°) + (-2x² + 3x) = (6x2 - 7x3 –​

PolinaCat29 · Answer

X + y = 6
xy = - 3

x = 6 - y
y( 6 - y ) = - 3
6y - y^2 = - 3
y^2 - 6y - 3 = 0
D = 36 + 12 = 48
√ D = √ 48 = 4 √ 3
y1 = ( 6 + 4 √ 3 ) : 2 = 3 + 2 √ 3
y2 = 3 - 2 √ 3
x = 6 - y
x1 = 6 - ( 3 + 2 √ 3 ) = 3 - 2 √ 3
x2 = 6 - ( 3 - 2 √ 3 ) = 3 + 2 √ 3

x^4 = ?
1) ( 3 - 2 √ 3 )^4 = ?
( 3 - 2 √ 3 )^2 = 9 - 12*3 + 4*3 = 9 - 36 + 12 = - 15
( 3 - 2 √ 3 )^4 = - 15 * ( - 15 ) = 225
2) ( 3 + 2 √ 3 )^2 = 9 + 12*3 + 4*3 = 9 + 36 + 12 = 57
( 3 - 2 √ 3 )^4 = 57 * 57 = 3249

1) X^4 + y^4 = 225 + 3249 = 3474
2) X^4 + y^4 = 57 + 225 = 282

2 6x2 – 7x – (3x2 + 47°) + (-2x² + 3x) = (6x2 - 7x3 –​

2 6x2 – 7x – (3x2 + 47°) + (-2x² + 3x) = (6x2 - 7x3 –