f(x) = 1/3 * x^3f'(x) = 1/3 * 3x^2 = x^2 g(x) = -x^2+3xg'(x) = -2x+3f'(x)<g'(x)x^2<-2x+3x^2+2x-3<0(x-1)(x+3)<0 + - +---(-3)(1)>x-3<x<1ответ: -3<x<1