Реши уравнение
(2x−17)^2−5(2x−17)+6=0.
2x - 17 = t
t^2 - 5t + 6 = 0
D = 25 - 4*6 = 1
t12 = (5 +- 1)/2 = 2 3
t1 = 2
2x - 17 = 2
2x = 19
x = 19/2 = 9.5
t2 = 3
2x - 17 = 3
2x = 20
x = 10
ответ (10, 9.5)
