Сократите дробь: 1) x^2-x-6/x^2-3x-10 2) x^2-6x-7/x^2-9x+14 - вопрос №1758099126231022672914 от TanyaVasutina 19.04.2020 06:28

Question

Алгебра: Сократите дробь: 1) x^2-x-6/x^2-3x-10 2) x^2-6x-7/x^2-9x+14 ! !

TanyaVasutina · Answer

1)x^2 - x - 6D = 1 + 4 * 6 = 25x1 = (1 + 5) / 2 = 3x2 = (1 - 5) / 2 = -2x^2 - x - 6 = (x - 3)(x + 2)x^2 - 3x - 10 D = 9 + 40 = 49x1 = (3 + 7) / 2 = 5x2 = (3 - 7) / 2 = -2x^2 - 3x - 10 = (x - 5)(x + 2)Сокращаем на х + 2( х не равно 2), получаем (х-3)/(х-5)2)x^2 - 6x - 7D = 36 + 28 = 64x1 = (6 + 8) / 2 = 7x2 = (6 - 8) / 2 = -1x^2 - 6x - 7 = (x - 7)(x + 1)2)x^2-9x+14D = 81 - 56 = 25х1 = (9 + 5) / 2 = 7х2 = (9 - 5) / 2 = 2x^2-9x+14 = (х - 2)(х - 7)Сокращаем на х - 7(х не равно 7), получаем (х + 1)/(х...