Г)x^3-11x^2+28x=0 д)x^3+7x^2=18x е)5x^4-6x^3+x^2=0 - вопрос №1966654311228037218546320 от shevchukmaria2 29.04.2020 04:24

Question

Алгебра: Г)x^3-11x^2+28x=0 д)x^3+7x^2=18x е)5x^4-6x^3+x^2=0

shevchukmaria2 · Answer

X(x^2-11x+28) = 0X=0      x^2-11x+28 =0           D = 121 - 112 = 9= 3^2           X1 = 7 X2=4x^3+7x^2-18x = 0x(x^2 +7x - 18) = 0x=0    x^2+7x-18 = 0         D = 49 +72 = 121 = 11^2         x1 = 2 X2 = -95x^4-6x^3+x^2=0X^2(5x^2 - 6x + 1) =0x^2 =0      5x^2 - 6x +1 =0x = 0        D = 36 -20 = 16 = 4^2               x1 = 1    x2=0.2...