2sin(x-7п/2)*sin x = корень из 3*cos x - вопрос №21847802723 от Tusovik 26.03.2022 21:29

Question

Алгебра: 2sin(x-7п/2)*sin x = корень из 3*cos x

Tusovik · Answer

-2*sin(x - 7π/2)*sinx = √3*cosx-2*sin(x - (4π - π/2))*sinx = √3*cosx-2*sin(x - 4π + π/2)*sinx = √3*cosx-2*sin(x + π/2)*sinx = √3*cosx-2*cosx*sinx - √3*cosx = 0cosx*(2sinx + √3) = 01) cosx = 0x = π/2 + πk2) 2sinx + √3 = 0sinx = -√3/2x = -π/3 + 2πkx = -2π/3 + 2πk...