Ну не пойму я вычислить 5-членов последовательности: 1) xn=1/2n-1 2) xn=4n^2+3n+2

1) Xn = 1/ (2n -1).
x1 = 1 / (2*1 -1) = 1/(2 - 1) =  1;
X2 = 1/(2*2 -1) = 1/(4 - 1) = 1/3 ;
 X3 = 1/(2*3 -1) = 1/(6 - 1) = 1/5;
X4 = 1/(2*4 -1) = 1/(8 - 1) = 1/7;
X5 = 1/(2*5 -1) = 1/(10 -1) = 1/9.
Xn  1; 1/3 1/5; 1/7; 1/9

2) Xn =4n^2 + 3n + 2;
X1 = 4*1^2 + 3*1 + 2 = 4+3+2 = 9;
X2 = 4*2^2 + 3*2 + 2 = 16+6+2 = 24;
 X3 = 4*3^2 + 3*3 + 2 = 36+9+2 = 47;
 X4 = 4*4^2 + 3*4 + 2 = 64 + 12 + 2 = 78;
X5 = 4* 5^2 + 3*5 + 2 = 100+15+2 = 117.
Xn  9,  24,  47, 78, 117