Надо! cos π/8 cosx-sin π/8 sinx ≤ -√3/2 - вопрос №33316828832 от danchikpozitiv 06.08.2020 04:19

Question

Алгебра: Надо! cos π/8 cosx-sin π/8 sinx ≤ -√3/2

danchikpozitiv · Answer

cos π/8 cosx-sin π/8 sinx ≤ -√3/2cos(π/8+x)≤-√3/25π/6+2πn≤π/8+x≤7π/6+2πn, n∈Z5π/6-π/8+2πn≤x≤7π/6-π/8+2πn, n∈Z17π/24+2πn≤x≤25π/24+2πn, n∈Zx∈[17π/24+2πn; 25π/24+2πn], n∈Z...