1.arcsin√2/2 2.arcsin(-1/2) 3.arccos(-1/2) 4.arctg√3 - вопрос №407583412221231243522263 от kolyakorolev 03.03.2022 18:25

Question

Алгебра: 1.arcsin√2/2 2.arcsin(-1/2) 3.arccos(-1/2) 4.arctg√3 5.sin2x=√2/2 6.cos3x=1 7.tgx/2=1 8.ctg4x=0

kolyakorolev · Answer

1.arcsin√2/2=π/42.arcsin(-1/2)=-π/4 3.arccos(-1/2)=2π/3 4.arctg√3=π/3 5.sin2x=√2/22x=(-1)^n*π/4+πnx=(-1)^n*π/8+πn/26.cos3x=13x=2πnx=2πn/3 7.tgx/2=1 x/2=π/4+πnx=π/2+2πn 8.ctg4x=04x=π/2+πnx=π/8+πn/4...