Cos x + cos 4x +cos 7x=0 sin2xsin6x - cosx cos 3x - вопрос №4092418470263 от andrei271 06.04.2021 04:05

Question

Алгебра: Cos x + cos 4x +cos 7x=0 sin2xsin6x - cosx cos 3x

andrei271 · Answer

1)cos x + cos 4x +cos 7x=02cos4xcos3x+cos4x=0cos4x(2cos3x+1)=0cos4x=0⇒4x=π/2+πn⇒x=π/8+πn/4cos3x=-1/2⇒3x=+-2π/3+2πn⇒x=+-2π/9+2πn /32)sin2xsin6x - cosx cos 3x =1/2cos4x-1/2cos8x-1/2cos2x-1/2cos4x=-1/2(cos8x+cos2x)==-1/2*2cos5xcos3x=-cos5xcos3x...