1)4х^2-11х+6=0 2)2(2-х)=7-3(2х+4) 3)решите сист урав ху-х=2 ху-ху^2=8

4x² - 11x + 6 = 0
D = b² - 4ac = (-11)² - 4 × 4 × 6 =121 - 96  = 25 = 5²
x1 = ( 11 + 5)/ 8 = 2
x2 = ( 11 - 5) / 8 = 0,75

4 - 2x = 7 - 6x - 12
- 2x + 6x = - 4 - 5
4x = - 9
x = - 9/4
x = - 2,25