Решите уравнения 1)х^2+3x+2=0. 2)-х^2-2х+24=0. - вопрос №458474612320222240327120425 от 3105nikitos2006 14.11.2022 05:23

Question

Алгебра: Решите уравнения 1)х^2+3x+2=0. 2)-х^2-2х+24=0. 3) х^2-7х+12=0. 4)-х^2-5х+6=0

3105nikitos2006 · Answer

X² + 3x + 2 = 0D = b² - 4ac = 9 - 4 × 2 = 1x1 = ( - 3 + 1) / 2 = - 1x2 = ( - 3 - 1) / 2 = -2- x² - 2x + 24 = 0x² + 2x ² - 24 = 0D = b² - 4ac = 4 - 4 × (-24) = 4 + 96 = 100 = 10²x1 = ( - 2 + 10) / 2 = 4x2 = ( - 2 - 10) / 2 = - 6x² - 7x + 12 = 0D = b² - 4ac = 49 - 4 × 12 = 1x1 = ( 7 + 1)/2 = 4x2 = ( 7 - 1) / 2 = 3- x² - 5x + 6 =0x² + 5x - 6 = 0D =b² - 4ac = 25 - 4 × ( - 6) = 49 = 7²x1 = ( - 5 + 7) / 2 = 1x2 = ( - 5 - 7)  / 2 = - 6...