Для функции f(x) = 3x-0,2x 2 найдите f(-15) f(0,2) - вопрос №46775873022150223 от yakovenko040320 31.01.2020 13:28

Question

Алгебра: Для функции f(x) = 3x-0,2x 2 найдите f(-15) f(0,2) f(2/3)

yakovenko040320 · Answer

F(-15) = 3*(-15) - 0.2*(-15)² = -45 -0.2*225 = -45 -45 = -90

f(0.2) = 3*0.2 - 0.2*(0.2)² = 0.6 - 0.008 = 0.592

f(2/3) = 3*(2/3) - 0.2 * (2/3)² = 2 - 0.2 * (4/9) = 2 - (1/5) * (4/9)=
= 2 - (4/45) = 90/45 - 4/45 = 86/45 = 1 ⁴¹/₄₅