Решите уравнение: 1) (2х-1)(4х^2+2х+1)=23+4х(2х^2-3) 2) 16х(4х^2-5)+17=(4х+1)(16х^2-4х+1). : (

1)( 2x - 1)(4x² + 2x + 1) = 23 + 4x( 2x² -3)
(2x)³ - 1³ = 23 + 8x³ - 12x
8x³ - 8x³ + 12x = 1 + 23
12x = 24
x = 24/12
x = 2

2) 16x(4x² - 5) + 17 = ( 4x + 1)(16x² - 4x + 1)
64x³ - 80x + 17 = (4x)³ + 1³
64x³ - 80x + 17 = 64x³ + 1
64x³- 64x³ - 80x = 1 - 17
- 80x = - 16
80x = 16
x = 16/80
x = 0,2