1) а1=3, а16= -5. знайти s16 2) d= -3, an= -15, sn= -36. знайти а1, n

1)a1=3,a16=-5
sn=n/2(a1+an)
s16=16/2(a1+a16)
s16=8(3+(-5))=8.(-2)=-16
s16=-16
2)d=-3,an=-15,sn=-36
an=a1+(n-1)d
a1=an-(n-1)d,a1=-15-(n-1).(-3)=-15+3n-3=3n-18
sn=n/2(a1+an),
-36=n/2(3n-18-15)=n/2(3n-33)
-72=n(3n-33), -72=3.n.(n-11),-24=n(n-11)
nˇ2-11n+24=0, (n-3)(n-8)=0
a)n=3,a1=-9
b)n=8,a1=6