Решите систему уравнений : x+3/4 - y+2/2 = 0 3x+y=1

( x + 3 )/4 - ( y + 2)/2 = 0
x + 3 - 2( y + 2 ) = 0
x + 3 - 2y - 4 = 0
3x + y = 1
y = 1 - 3x
2y = 2 - 6x
2y = x - 1
2 - 6x = x - 1
7x = 3
x = 3/7
y = 1 - 3•( 3/7 ) = 1 - 9/7 = 1 - 1 2/7 = - 2/7
ответ ( 3/7 ; - 2/7 )