)1)(sin23°cos22°+cos23°sin22°)(cos24°cos21°-sin24°sin21°) - вопрос №57228901232223222421242123 от elinashovhalova 04.12.2022 23:42

Question

Алгебра: )1)(sin23°cos22°+cos23°sin22°)(cos24°cos21°-sin24°sin21°) 2)(sin(a+3ß)+sin(a-3ß))/(sin(a+3ß)-sin(a-3ß))*ctga 3)(sin38°+sin22°)/cos8°

elinashovhalova · Answer

1sin(23+22)*cos(24+21)=sin45*cos45=0,5sin90=0,5*1=0,522sinacos3b/2sin3bcosa *ctga=tga*ctg3b *ctga=ctg3b32sin30cos8/cos8=2sin30=2*1/2=1...