Sin(pi/3-2x)*cos(pi/3-2x)≥-√3/4 найдите решения неравенства - вопрос №5737882323234 от tearprincess200225 25.01.2022 16:53

Question

Алгебра: Sin(pi/3-2x)*cos(pi/3-2x)≥-√3/4 найдите решения неравенства

tearprincess200225 · Answer

1/2*sin(2π/3-4x)≥-√3/4sin(4x-2π/3)≤√3/22π/3+2πn≤4x-2π/3≤7π/3+2πn4π/3+2πn≤4x≤3π+2πnπ/3+πn/2≤x≤3π/4+πn/2x∈[π/3+πn/2;3π/4+πn/2,n∈z]...