Log 8 (x+10) - log 8 x = 1 log 5 (x+12) + log 5 (x-12) - вопрос №57937888108151251221231 от Виктория20052808 14.09.2020 21:41

Question

Алгебра: Log 8 (x+10) - log 8 x = 1 log 5 (x+12) + log 5 (x-12) = 2 log 1//2 (3x-1) = -4

Виктория20052808 · Answer

1) log 8 (x+10)/x = log 8 8x+10/x=8x+10=8x7x=10x=10/72)log 5 (x+12)(x-12) = log 5 25(x+12)(x-12)=25x^2-144=25x^2=169x=+-133)log 1/2 (3x-1) = log 1/2 163x-1=163x=17x=17/3...