A) 3/3/5×1/3+6/4/9: 2= б) 2/5/6-1/1/5×1/1/9+1/5/7: - вопрос №5807560335136492256115119157117529311 от djdjsjsj 26.11.2020 01:21

Question

Алгебра: A) 3/3/5×1/3+6/4/9: 2= б) 2/5/6-1/1/5×1/1/9+1/5/7: 1/1/7= в)5/2/9: (3-1/19×2/2/5)+4/5=

djdjsjsj · Answer

A) 3/3/5×1/3+6/4/9:2= 18/5*1/3+58/9*1/2=6/5+29/9=54/45+145/45=199/45=4 19/45;/// б) 2/5/6-1/1/5×1/1/9+1/5/7:1/1/7= 17/6-6/5*10/9+12/7*7/8= 17/6-4/3+3/2=17-8+9/6=18/6=3; в)5/2/9:(3-1/19×2/2/5)+4/5= 47/9:(3-1/19*12/5)+4/5= 47/9:(3-12/95)+4/5= 47/9:(2 95/95-12/95)+4/5= 47/9:(2 83/95)+4/5= 47/9*95/273+4/5=4465/2457+4/5= 22325+9828/12285= 32153/12285=2 7583/12285...