Сократить дроби 50 . x²-1/x²-x= x²/x²+x= x²-1/x²+x= - вопрос №601025501139 от Kubrex 24.10.2022 10:22

Question

Алгебра: Сократить дроби 50 . x²-1/x²-x= x²/x²+x= x²-1/x²+x= a/am= a-3b/a²-9b²= pq/q= m²-4n²/m+2n=

Kubrex · Answer

X^2-1/x^2-x = (x-1)(x+1)/x(x-1) = x+1/xx^2/x^2+x = x^2/x(x+1) = x/x+1x^2-1/x^2+x = (x-1)(x+1)/x(x+1) = x-1/xa/am=1/ma-3b/a^2-9b^2 = a-3b/(a-3b)(a+3b) = 1/a+3bpq/q = pm^2-4n^2/m+2n = (m-2n)(m+2n)/m+2n = m-2n...