Решите уравнения: (х+3)(х-2)=0, (2х-1/3(+3)=0, (х-5)(х+3)(2х-1)=0, - вопрос №6068576320213305321012 от sahakohela 04.11.2022 03:29

Question

Алгебра: Решите уравнения: (х+3)(х-2)=0, (2х-1/3(+3)=0, (х-5)(х+3)(2х-1)=0, (х-1,2)(х+3,4)(1+2х)=0, (1-4х)(3х+2)(2-5х)=0

sahakohela · Answer

(х+3)(х-2)=0х+3=0. ИЛИ. х -2 =0х=-3. х=2(2х - 1/3)(3х+3)=02х - 1/3=0. Или 3х+3=02х =1/3. 3х =3х=1/3:2. х=3:3х=1/6. х=1(х+5)(х+3)(2х-1)=0х+5=0. х+3=0. 2х-1=0х =-5. х=-3. 2х =-1 х=-1/2(х-1,2)(х+3,4)(1+2х)=0х - 1,2=0. х+3.4=0. 1+2х =0х =1,2. х=-3.4. 2х =-1 х=-1/2(1-4х)(3х +2)(2-5х)=01-4х=0. 3х+2=0. 2-5х=0-4х=-1. 3х=-2. -5х=-2х=1/4. х=-2/3. х=2/5...