Решить неравенство 1) 3(x-2)+x< 4x+1 2) 5(x+2)-x> 3(x-1)+x

1) 3(х-2)+х<4х+1
3х-6+х<4х+1
4х-6<4х+1
4х-6-4х-1<0
-7<0
2) 5(х+2)-х > 3(х-1)+х
5х+10-х>3х-3+х
4х+10>4х-3
4х+10-4х+3>0
13>0

1) 3x-6+x <4x+1
4x-6 <4x+1
-6 <1
2) 5x+10-x> 3x-3+x
4x+10> 4x-3
10> -3