:1) (х+2)^2=4(х+4) 2) 4(х-1)^2=(х+2)^2 3) (3х-1)^2=3(1-2х) - вопрос №69100411224424122233123124323 от Daniil2263 11.12.2020 06:48

Question

Алгебра: :1) (х+2)^2=4(х+4) 2) 4(х-1)^2=(х+2)^2 3) (3х-1)^2=3(1-2х) 4) (х+3)^2=3(х+1)^2

Daniil2263 · Answer

1)x^2+4x+4=4x+16x^2=16-4x^2=12x1,2=2/32)4(x^2-2x+1)=x^2+4x+44x^2-8x+4=x^2+4x+44x^2-12x-4x=0x^2-4x=0(x-2)(x+2)=0X=2  x=-23)9x^2-6x+1=3-6x9x^2-2=0(3x- /2)(3x+/2)=03x=/2    3x=-/2x=/2:3   x=-/2:3...