Найдите корни уравнения x(x-3)(x+1)(x+4)=-35

X(x + 1)(x - 3)(x + 4) = - 35
(x^2 + x)(x^2 + x - 12) = - 35
x^2 + x = t

t (t - 12) + 35 = 0 
t^2 - 12t + 35 = 0 
D = 144 - 35*4 = 4 = 2^2
t1  =( 12 + 2)/2  = 7
t2 = (12 - 2)/2 = 5

#1 
x^2 + x = 7
x^2 + x - 7 = 0 
D = 1 + 4*7 = 29
x1 = ( - 1 +√29)/2
x2 = ( - 1 - √29)/2

#2
x^2 + x = 5
x^2 + x - 5 = 0 
D = 1 + 4*5 = 21
x3 = ( - 1 +√21)/2
x4 = ( - 1 - √21)/2