Решите уравнение: 6(y+1)^2+2 (y+1) (y^2-y+1) - 2 (y+1)^3 = -22

6(у^2+2у+1)+2(у^3+1)-(2(у^3+3у^2+3у+1)=-22;
6у^2+12у+6+2у^3+2-2у^3-6у^2-6у-2=-22;
6у+6=-22; 6у=-22-6; 6у=-28;
у=-28/6= -14/3= -4 цел 2/3.