(x+8)^2+1=0 (4x+8)^2-12=0 (3-2x)^2=36 (2+11x)^2=6 - вопрос №818878782104821203223621126 от Araikavipv 10.03.2021 12:46

Question

Алгебра: (x+8)^2+1=0 (4x+8)^2-12=0 (3-2x)^2=36 (2+11x)^2=6

Araikavipv · Answer

1)(x+8)^2+1=0(x+8)^2=-1x^2+16x+65=-1x^2+16x+66=0x ∉ R2)(4x+8)^2-12=016x^2+64x+64-12=016x^2+64x+52=0x₁= x₂=3)(3-2x)^2=369-2x+4x^2=364x^2-12x-27=0x₁= -  x₂=4)(2+11x)^2=6121x^2+44x+4=6121x^2+44x-2=0x₁=  x₂=...