Вычислите 1) (49^2/3)^3/4 2) (625^-3/8)^2/3 3) (64^1/4)^-2/3 - вопрос №81902601492334262538233641423 от Inozemceva1981 11.02.2021 19:00

Question

Алгебра: Вычислите 1) (49^2/3)^3/4 2) (625^-3/8)^2/3 3) (64^1/4)^-2/3

Inozemceva1981 · Answer

1) (49^2/3)^3/4=49^(2/3*3/4)=49^½=✓49=72) (625^-3/8)^2/3=625^(-⅜*⅔)=625^-¼=1 / 625^¼= 1 / ⁴√625=1/5=0,23) (64^1/4)^-2/3=64^(¼*(-⅔))=64^-1/6= 1 / корень 6 стпени√64=½=0,5...