Решите по действиям а)(1/3)^3*(-1/9): (1/3)^5 б)1,5^4: - вопрос №855319713319135154153150 от Kuznezovamargo 28.01.2021 15:29

Question

Алгебра: Решите по действиям а)(1/3)^3*(-1/9): (1/3)^5 б)1,5^4: (-1,5)^3*(-1,5)^0: 1,5 в)(8/27): (2/3)^2*(16/81)^6

Kuznezovamargo · Answer

А)(1/3)^3*(-1/9):(1/3)^5= -1/31. -1/9= (-1/3)^32. -(1/3)^3*(1/3)^3:(1/3)^5= -(1/3)^6:(1/3)^5= -1/3б)1,5^4:(-1,5)^3*(-1,5)^0:1,5= -11. (-1,5)^0=12. -1,5^4:1,5^3:1,5= -1,5:1,5= -1в)(8/27):(2/3)^2*(16/81)^6= (2/3)^251. 8/27=(2/3)^32. (16/81)^6= ((2/3)^4)^6= (2/3)^243. (2/3)^3:(2/3)^2*(2/3)^24= 2/3*(2/3)^24= (2/3)^25...