Найти уравнение первообразной а) f(x)=x^3+2, a(-1: 3) б) f(x)=x+3 b(1; 2) в) f(x)=2+x^2 a(3; 1)

A) F(x) = x⁴/4 + 2x + C;
A(-1, 3)
3 = (-1)⁴/4 + 2 * (-1) + C = 0.25 - 2 + C;
3 = -1.75 + C => C = 3 + 1.75 = 4.75;

б) F(x) = x²/2 + 3x + C;
B(1, 2)
2 = 1/2 + 3*1 + C;
C = 2 - 3.5 = -1.5;

в) F(x) = 2x + x³/3 + C;
A(3, 1)
1 = 2*3 + 27/3 + C = 15 + C;
C = 1 - 15 = -14;