Разложите на множители. 25a³-1 125+b³ 1-36y³ c³-4ac+4a³

25a³-1=
125+b³=(5+b)(25-5b+b²
1-36y³=

25a³-1 =(∛25a)³ -1³= (∛25a-1)((∛25a)²-∛25a+1)

125+b³=5³+b³ =(5+b)(25-5b+b²)

1-36y³=1³-(∛36y)³= (1-∛36y)(1+∛36y+(∛36y)²)

c³-4ac+4a³=c³-2ac-2ac+4a³=c(c²-2a)-2a(c-2a²)