1)tg(3x+pi/4)+1=0 2)2cos(3x/2-pi/3)=-1 3)2sin x - вопрос №899491613410223231321230 от ValeriaSalvatore 18.11.2022 21:31

Question

Алгебра: 1)tg(3x+pi/4)+1=0 2)2cos(3x/2-pi/3)=-1 3)2sin x - 1 / 2cos x +√3)=0

ValeriaSalvatore · Answer

Tg(3x/2-π/3)=-13x/2-π/3=-π/4+πk3x/2=π/3-π/4+πk3x/2=π/12+πkx=2/3*π/12+2/3*πkx=π/18+2k/32)cos(3x/2-π/3)=-1/23x/2-π/3=±(π-π/3)+2πk3x/2=π/3±2π/3+2πkx=2/3(π/3±2π/3+2πk)...