ctg(x/3 + 2π/3) > -1;
πn < x/3 + 2π/3 < 3π/4 + πn, n∈Z;
-2π/3 + πn < x/3 < π/12 + πn, n∈Z;
-2π + 3πn < x < π/4 + 3πn, n∈Z;
ответ: х∈(-2π + 3πn; π/4 + 3πn), n∈Z
