Найдите координаты вершины параболы: g(x) =x^2-4x+1 g(x) =x^2+6x g(x)=10-2x+5x^2 g(x) =3-x-x^2 ! заранее )

1) g(x) = x^2 - 4x + 1
Xв = -b/2a = - -4/2*1 = 2
Yв = 2^2 - 4*2 + 1 = -3
(2; -3)

2) g(x) = x^2 + 6x
Хв = -b/2a = - 6/2*1 = -3
Yв = (-3)^2 + 6*(-3) = -9
(-3; -9)

3) g(x) = 10 - 2x + 5x^2
Xв = -b/2a = - -2/2*5 = 1/5
Yв = 10 - 2*1/5 + 5*(1/5)^2 = 8 4/5
(1/5; 8 4/5)

4) g(x) = 3 - x - x^2
Xв = -b/2a = - -1/2*(-1) = -1/2
Yв = 3 - (-1/2) - (-1/2)^2 = 3 + 1/2 - 1/4 = 3 1/4
(-1/2; 3 1/4)