написать про компанию на английском, используя некоторые словосочетания из таблицы Espace Mode
COMPANY FACT SHEET
Location: Grenoble
Main activity: Clothes manufacturers and retaliers
Customers: Men and women from all walks of life in the age range 16–25.
We also supply wholesale products to agents and mail-order catalogues.
Market position: We are among the French top three in the clothing sector.
Staff: We employ nearly 300 people.
Financial information: Annual turnover of over 190 million euros.
Profits of 7.6 million euros, i.e., 4 per cent of sales.
Future plans: We are working on exciting new designs which reflect a completely new concept in teenage fashion. Espace Mode is set to become the leader of the European fashion market.

when i get up early i start preparing to crusade to the my beautiful school and i always start with breakfast. first of all i cooking a perfect burgers with 24 carats edible gold dust, it's my favorite dish. at that time i'm making a cup of real british yorkshire tea with sweet cookies entitled oreo. and now i will tell you, about the main dish named poutine, it's canadian dish of french fries and cottage cheese with special sause. i like to add a marbled beef of japanese black cattle and also with the second additive beluga black caviar. and for dessert i eat ice cream covered a ten 1,5 carat diamonds cone. it exactly looks my usual breakfast, you can take my word(;

Сначала формулы . затем формулы двойного угла sin2α=2sinαcosα cos2α=cos²α-sin²α=cos²α-(1-cos²α)=2cos²α-1⇒  2cos²α=1+cos2α cos2α=cos²α-sin²α=1-sin²α-sin²α=1-2sin²α⇒  2sin²α=1-cos2α а) сos75°cos105°=cos(90°-15°)·cos(90°+15°)== sin15°(-sin15°)=-sin²15°=-(1-cos30°)/2=(cos30°-1)/2= ((√3/2)-1)/2=0,25√3-0,5б) sin75°sin15°=°sin(90°-15°)sin15°=cos15° sin15°=sin30°/2=1/4=0,25в) sin105°cos15°=sin(180°-75°)cos15°=sin75°cos15°=sin(90°-15°)cos15°=cos15°cos15°=(1+cos30°)/2=(1+(√3/2))/2=0,5 +0,25√3 2 способ формулы cosα·cosβ=0,5cos(α-β)+0,5cos(α+β) sinα·sinβ=0,5cos(α-β)-0,5cos(α+β) sinα·cosβ=0,5sin(α+β)+0,5sin(α-β) а) сos75°cos105°=0,5cos(75°-105°)+0,5cos(75°+105°)=0,5cos(-30°)+0,5 cos180°==0,5· √3/2+0,5·(-1)=0,25√3-0,5б) sin75°sin15°=0,5cos(75°-15°)-0,5cos(75°+15° )=0,5cos60°-0,5 cos90°=0,5·0,5=0,25в) sin105°cos15°=0,5sin(105°+15°)+0,5sin(105°-15°)= =0,5sin120°+0,5sin90°==0,5 sin(180°-60°)+0,5·1=0,5 sin 60°+0,5=0,25√3+0,5