Identical do the amount of the substance contained in 44 g of CO2 and 2 g of hydrogen H2?

given:
m(СО2) = 44 g
m(Н2) = 4 g
find:
ν( СО2) - ?
ν(Н2) - ?
Solution:
1- way:
М(СО2) = 44 g/mol
44 g СО2  х mol СО2
44 g СО2 1 mol СО2
х= (44 g  • 1 mol)/(44 g)   =1 mol
2- way:
М(СО2) = 44 g/mol
ν=m/М  ;ν(СО₂) =(m(СО₂))/(М(СО₂))  = (44 g)/(44 g/mol)  = 1 mol.
1- way:
М(Н2) =2 g/моль
2 g Н2  х mol Н2
2 g Н2 1 mol Н2
х= (2 g  • 1 mol)/(2 g)   =1 mol
2- way:
М(Н2) = 2 g/mol
ν=m/М  ;ν(Н₂) =(m(Н₂))/(М(Н₂))  = (2 g)/(2 g/mol)  = 1 mol.
Answer:ν(СО2) =  1 mol; ν(Н2) =  1 mol–Identical.