Точка P не належить площині трикутника ABC і знаходиться на відстані 8 см від кожної з прямих, які містять його сторони. Проекцією точки P на площину ABC є точка O, що належить даному трикутнику, якщо AB=CD=17 см, AC=16 см​

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Объяснение:

Если сторона и два прилежащих к ней угла одного треугольника соответственно равны стороне и двум прилежащим к ней углам другого треугольника, то такие треугольники равны.

Дано: ΔАВС, ΔА₁В₁С₁.

          АС = А₁С₁, ∠А = ∠А₁, ∠С = ∠С₁

Доказать:

          ΔАВС = ΔА₁В₁С₁.

Доказательство:

Наложим треугольники друг на друга равными сторонами так, чтобы вершины В и В₁ оказались по одну сторону от прямой АС.

Равные стороны совпадут, совпадут и углы, прилежащие к ним. Значит, совпадут и вершины В и В₁.