(a¹²)⁸= k*k⁸= (k¹²)¹¹/k⁶⁹= (c⁸)⁹/c³⁰= (a¹²)⁸= (c⁹)⁶*c⁴= - вопрос №4825269 от Ztduvuycc 16.07.2020 20:28

Question

Геометрия: (a¹²)⁸= k*k⁸= (k¹²)¹¹/k⁶⁹= (c⁸)⁹/c³⁰= (a¹²)⁸= (c⁹)⁶*c⁴= (d¹²)⁵*d¹⁵= (k²)⁹*k⁸= (k¹⁴)⁶/k³¹= (k-3)¹²/(k-3)⁵= решите все много

Ztduvuycc · Answer

(а¹²)⁸= а ¹²*⁸= а ⁹⁶к * к⁸=к¹  * к⁸= к⁹(k¹²)¹¹/ k⁶⁹= k ¹³²⁻⁶⁹= k⁶³(c⁸)⁹ / c ³⁰ = c ⁷²⁻³⁰= c ⁴²(a ¹²)⁸= a ⁹⁶(c⁹)⁶ * c⁴= c ⁵⁴⁺⁴= c ⁵⁸(d¹²)⁵ * d¹⁵= d⁶⁰⁺¹⁵= d⁷⁵(k²)⁹ *k⁸= k¹⁸⁺⁸= k²⁶(k¹⁴)⁶ / k³¹= k⁸⁴⁻³¹=k⁵³(k-3)¹² / (k-3)⁵ = (k-3)¹²⁻⁵ = (k-3)⁷...