Информатика (с готовой блок-схемо)
1.для данного вещественного ж найти значение следующей функции f
f(x)= -x, если х< 0;
х^2, если 0 4х, если х> 2
2. вычислить сумму все двузначных нечетных чисел.

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1) a := 4;  

b := 6;

b := 8 + a * b;

a := b / 4 * a.

а = 4

b = 6

b = 8 + 4 * 6 = 32

a = 32 / 4 * 4 = 32 / 16 = 2

2) a := 3;

b := 6;

b := 12 + a * b;

a := b / 5 * a.

a = 3

b = 6

b = 12 + 3 * 8 = 30

a = 30 / 5 * 3 =  6 * 3 = 18

3) a := 8;

b := 8 + a / 2;

a := a – b / 2.

a = 8

b = 8 + 8 / 2 = 12

a = 8 - 12 / 2 = 8 - 6 = 2

4) a := 2;

b := 6;

b := 12 + a * b;

a := b / 4 * a.

a = 2

b = 6

b = 12 + 2 * 6 = 12 + 12 = 24

a = 24 / 4 * 2 = 6 * 2 = 12

5) a := 3;

b := 8 + 2 * a;

a := b / 2 * a.

a = 3

b = 8 + 2 * 3 = 8 + 6 = 14

a = 14 / 2 * 3 = 7 * 3 = 21

6) f := 21;

e := 10;

f := 5 * f + 5;

e := f – 10 – e * 5.

f = 21

e = 10

f = 5 * 21 + 5 = 105 + 5 = 110

e = 110 - 10 - 10 * 5 = 100 - 50 = 50

7) a := 14;

b := 4;

a := a / 2 - b;

b := (a * b) / 2;

b := a + b

a = 14

b = 4

a = 14 / 2 - 4 = 7-4 = 3

b = ( 3 * 4) / 2 = 12 / 2 = 6

b = 3 + 6 = 9

8) b := 5;

a := -3;

a := 7 + a * b;

b := a / 2 + b

b =5

a = -3

a = 7 + (-3 * 5) = 7 + (-15) = -8

b = -8/2 + 5 = -4 +5 = 1

9) a := 4;

b := 5;

a := b + 15;

b := 100 / a * 4.

a = 4

b = 5

a = 5 + 15 = 20

b = 100 / 20 * 4 = 5 * 4 = 20

10) b := 8;

a := 10;

b := b + a * 2;

a := 29 - a;

b = 8

a = 10

b = 8 + 10 * 2 = 8 + 20 = 28

a = 29 - 10 = 19;

Объяснение:

//Как-то громоздко получилось, но я так вижу. Эх, выходные.
const n=5;
var a:array[1..n] of integer;
b:array[0..8] of integer;
ar:array[1..n] of integer;
i,c,j:integer;
begin
randomize;
writeln('Array:');
for i:=1 to n do
begin
a[i]:=random(8);
write(a[i]:4);
end;
for i:=1 to n do
 begin;
  for j:=0 to 8 do
    if a[i]=j then inc(b[j]);
 end;
for i:=1 to n do
 begin;
  for j:=0 to 8 do
   if (b[j]>1) and (a[i]=j) then a[i]:=9;
 if a[i]<>9 then
  begin;
   inc(c);
   ar[c]:=a[i];
  end;
 end;
 writeln;
 for i:=0 to 8 do writeln(i,'=',b[i]);
writeln;
writeln('Final array:');
for i:=1 to n do
if a[i]=9 then a[i]:=0;

for i:=1 to c do
begin;
 a[i]:=ar[i];
 write(a[i]:4);
end;
end.