#include<iostream>
using namespace std;
int main()
{
setlocale( LC_ALL, "Russian" );
float a,b,s;
int dp;
cout << "Привет! Я калькулятор!Какие действие вы будете выполнять:" << endl;
cout << "1. Сложение. " << endl;
cout << "2. Отнимание." << endl;
cout << "3. Умножение." << endl;
cout << "4. Деление." << endl;
cout << "Введите число для выбора действия" << endl;
cin >> dp;
switch(dp)
{
case 1:
cout << "Число a = " << endl;
cin >> a;
cout << "Число b = " << endl;
cin >> b;
s = a + b;
cout << "\n" << a << " * " << b << " = "<< s << endl;
break;
case 2:
cout << "Число a = " << endl;
cin >> a;
cout << "Число b = " << endl;
cin >> b;
s = a - b;
cout << "\n" << a << " * " << b << " = "<< s << endl;
break;
case 3:
cout << "Число a = " << endl;
cin >> a;
cout << "Число b = " << endl;
cin >> b;
s = a * b;
cout << "\n" << a << " * " << b << " = "<< s << endl;
break;
case 4:
cout << "Число a = " << endl;
cin >> a;
cout << "Число b = " << endl;
cin >> b;
s = a / b;
cout << "\n" << a << " / " << b << " = "<< s << endl;
break;
}
return 0;
}
1
ответ:
n = int(
lstr = (" ")
ns = []
i = 0
tot = 0
while i < n:
ns.append(int(
tot += int(lstr[i])
i += 1
if tot % 5 == 0 and len(ns) > 4:
sm = int(tot / 5)
ns = sorted(ns, reverse=true)
ps = "yes"
su = 0
sk = 0
b = false
for n in ns:
if n ! = 0 and b:
su == 0
sk += 1
b = false
break
if sk == 5:
ps = "no"
break
su += n
if abs(su) > abs(sm):
ps = "no"
break
if su == sm:
b = true
print(ps)
else:
print("no")
объяснение:
