Відповідь:
Бейсик Python
DIM N, S AS INTEGER
N = 1
S = 0
WHILE N <= 100
S = S + 30
N = N * 2
WEND
PRINT S
n = 1
s = 0
while n <= 100:
s = s + 30
n = n * 2
print(s)
Паскаль Алгоритмический язык
var n, s: integer;
begin
n := 1;
s := 0;
while n <= 100 do
begin
s := s + 30;
n := n * 2
end;
write(s)
end.
алг
нач
цел n, s
n := 1
s := 0
нц пока n <= 100
s := s + 30
n := n * 2
кц
вывод s
кон
Си++
#include <iostream>
using namespace std;
int main()
{
int n, s;
n = 1;
s = 0;
while (n <= 100)
{
s = s + 30;
n = n * 2;
}
cout « s « endl;
}
Пояснення:
#include <iostream>
int main() {
int arr[100], n, first = 0, second = 0;
std::cin >> n;
for (int i = 0; i < n; ++i)
std::cin >> arr[i];
for (int i = 1; i < n; ++i) {
const int diff = arr[i] - arr[i - 1];
if (diff > 0)
if (arr[i] <= 2000)
first += diff;
else if (arr[i - 1] >= 2000)
second += diff;
else {
first += 2000 - arr[i - 1];
second += arr[i] - 2000;
}
}
std::cout << first << ' ' << second;
return 0;
Объяснение:
язык python
