1)
program gt1;
var x,y:real;
begin
x:=-3.1;
while x<1 do
begin
x:=x+0.1;
y:=4*x*x*x-2*x*x+5;
writeln(y);
end;
end.
2)
program gt2;
var k,i:integer;
begin
k:=0;
for i:=11 to 20 do
begin
if(i mod 2=1)then k:=k+1;
end;
writeln(k);
end.
3)
program gt3;
var s,i:integer;
begin
s:=0;
for i:=1 to 100 do
begin
if(i mod 2=0)then s:=s+i;
end;
writeln(s);
end.
4)
program gt4;
var sum,a:real;
i,n:integer;
begin
sum:=0;
a:=0;
readln(n);
for i:=1 to n do begin
a:=1/((3*n-2)-(3*n+1));
Sum:=sum + a;
n:=n+1;
end;
write(sum);
end.
5)
program gt5;
var n,k:integer;
begin
k:=0;
while n>0 do
begin
n:=n div 10;
k:=k+1;
end;
writeln(k);
end.
c++
Объяснение:
#include <iostream>
using namespace std;
const int m = 6;
const int n = 4;
int main() {
int a[m][n];
/*Ввод массива*/
for(int i = 0;i < m;i++) {
for(int j = 0;j < n;j++) {
cout << "A[" << i << "][" << j << "] = ";
cin >> a[i][j];
}
}
int sum = 0;
int mult = 1;
for(int i = 0;i < m;i++) {
for(int j = 0;j < n;j++) {
sum += a[i][j];
mult *= a[i][j];
}
}
cout << "Sum = " << sum << endl << "Mult = " << mult;
}
