Задание 1
#include <iostream>
using namespace std;
int main() {
int a, b;
cin >> a >> b;
cout << a - b;
}
Задание 2
#include <iostream>
#include <math.h>
using namespace std;
int main() {
int a;
cin >> a;
cout << pow(a, 2) << ' ' << pow(a, 3)<< ' ' << pow(a, 5);
}
Задание 3
#include <iostream>
#include <math.h>
using namespace std;
int main() {
int a;
cin >> a;
cout << "The next number for the number " << a << " is " << a + 1 <<"!\n" <<"The previous number for the number "<< a << " is " << a - 1 <<"!";
}
Задание 4
#include <iostream>
#include <math.h>
using namespace std;
int main() {
int a;
cin >> a;
cout << (3 * pow(a, 3) + 18 * pow(a, 2)) * a + 12 * pow(a, 2) - 5;
}
Задание 5
#include <iostream>
#include <math.h>
using namespace std;
int main() {
int a, b, c;
cin >> a >> b >> c;
cout << a % 7 << "\n" << b % 7 << "\n" << c % 7;
}
Задание 6
#include <iostream>
#include <math.h>
using namespace std;
int main() {
int a, b, c, a1, b1, c1;
cin >> a >> a1 >> b >> b1 >> c >> c1;
cout << a1 % (8 - a) << "\n" << b1 % (8 - b) << "\n" << c1 % (8 - c);
}
Program Pr1;
uses crt;
var mas:array[1..15] of integer;
i,max,min,b,v:integer;
Begin
clrscr;
for i:=1 to 15 do mas[i]:=random(10);
for i:=1 to 15 do write(mas[i]);
max:=0;
min:=100000;
b:=0;
for i:=1 to 15 do begin
if mas[i]>max then max:=i;
if mas[i]<min then min:=i;
end;
if max>min then for i:=min to max div 2 do begin
v:=mas[max-b];
mas[max-b]:=mas[i];
mas[i]:=v;
b:=b+1;
end
else for i:=max to min div 2 do begin
v:=mas[min-b];
mas[min-b]:=mas[i];
mas[i]:=v;
b:=b+1;
end;
writeln();
for i:=1 to 15 do write(mas[i]);
end.
