Решить по информатике. тема массивы. ​

Uses graphABC;beginsetpenwidth(3);setwindowsize(600,700);ellipse(120,350,280,480);circle(200,300,60);circle(200,210,40);line(170,90,230,90);line(160,180,240,180);line(170,90,160,180);line(230,90,240,180);floodfill(200,173,clblack);floodfill(200,123,clblack); setbrushcolor(clblack);circle(190,200,5);circle(210,200,5);line(200,210,220,220);line(200,220,220,220);line(200,210,200,220);floodfill(204,214,clblack);setpenwidth(5);arc(200,230,10,180,0);line(70,320,170,250);line(230,250,330,300);line(300,450,350,200);
line(350,200,320,140);line(350,200,340,140);line(350,200,360,140);line(350,200,380,140);line(350,200,400,140);end.

var a: array [1..5, 1..7] of integer;

i,j,max,min: integer;

begin

for i:=1 to 5 do  

for j:=1 to 7 do  

A[i,j]:=random(100);

max:=-1;

min:=101;

for i:=1 to 5 do begin

for j:=1 to 7 do  

write(A[i,j]:5);

writeln();

end;

 

for i:=1 to 5 do  

for j:=1 to 7 do  

 if A[i,j]>max then max:=A[i,j];

for i:=1 to 5 do  

for j:=1 to 7 do  

 if A[i,j]<min then min:=A[i,j];

for i:=1 to 5 do  

for j:=1 to 7 do begin

 if A[i,j]=max then A[i,j]:=min

 else if A[i,j]=min then A[i,j]:=max;

end;

 

writeln();

for i:=1 to 5 do begin

for j:=1 to 7 do  

write(A[i,j]:5);

writeln();

end;

end.