дано
m(ppa H2SO4) = 196 g
W(H2SO4) = 10%
m(NaOH) - ?
m(H2SO4) = 196 * 10% / 100% = 19.6 g
H2SO4+2NaOH-->Na2SO4+2H2O
m(H2SO4) = 98 g/mol
n(H2SO4) = m/M = 19.6 / 98 = 0.2 mol
n(H2SO4) = 2n(NaOH)
n(NaOH) =2*0.2 = 0.4 mol
M(NaOH) = 40 g/mol
m(NaOH) = n*M =0.4 * 40 = 16 g
ответ 16 г
Объяснение:
