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Дано:
m (FeS2) = 150 г
w(прим) = 20 %
m (практ. Fe2O3) = 70 г
Найти:
wвых (Fe2O3)
Вычислим массу чистого FeS2:
w(чист) = 100% - w(прим) = 100% - 20% = 80%
150 г – 100%
х г - 80%
х = 150 г ∙ 80% \100% = 120 г
Вычислим теоретическую массу образовавшегося Fe2O3:
120 г х г
4FeS2 + 11O2 → 2Fe2O3 + 8SO2↑.
480г 320 г
120 г --- х г
480 г --- 320 г
х = 120 г ∙ 320 г\480г = 80 г
Вычислим практическую массу выхода продукта:
w(вых) = m(практ) ∙ 100%\ m(теор)
m(практ. Fe2O3) = 70 г ∙100%\80= 87,5%
ответ: wвых (Fe2O3)= 87,5%
