1) n(общ)=1+11+27+9=48
2) q(CH4)=n(CH4)/n(общ)=1/48=2.083%
q(H2O)=n(H2O)/n(общ)=11/48=22.92%
q(CO или СO2 )=n(CO CO2)/n(общ)=9/48=18.75%
q(H2)=n(H2)/n(общ)=27/48=56.25%
3) m(общ)=1*16+11*18+9*44+27*2=664 кг c (CO2)
4) w(CH4)=m(CH4)/m(общ)=16/664=2.41%
w(H2O)=m(H2O)/m(общ)=18*11/664=29.82%
w(CO2)=m(CO2)/m(общ)=44*9/664=59.64%
w(H2)=m(H2)/m(общ)= 27*2/664=8.133%
5) m(общ)=1*16+11*18+9*28+27*2= 520 кг c (CO)
w(CH4)=m(CH4)/m(общ)=16/520=3,077%
w(H2O)=m(H2O)/m(общ)=18*11/520=38.08%
w(CO)=m(CO)/m(общ)=28*9/520=48.46%
w(H2)=m(H2)/m(общ)= 27*2/520=10.38%
CH3
|
H2N-C-COOH + H2N-CH2-COOH + COOH-CH2-CH-COOH >
| | -2H2O
H NH2
CH3
|
-->H2N-C-C=O
| \
H N-CH2-C=O
| \
H N-CH-CH2-COOH
| |
H COOH
